Swift 重构:重载运算符
一、思路来源
研究自定义运算符的时候,又重新看了一下重载运算符,觉得挺有意思的,随手封装了几个。
二、基础类型 String 为例
重载乘法运算符:将一段字符串重复 n 次拼接在一起;
let c = "abc"*3;
print("c: \(c)");//c: abcabcabc
源码实现:
``` public extension String{
static func * (lhs: String, rhs: Int) -> String { return String(repeating: lhs, count: rhs); } } ```
三、对象类型 UIEdgeInsets 为例
重载加法运算符将:将 top, left, bottom, right 属性逐个求和;
``` let edg1 = UIEdgeInsets(top: 1, left: 2, bottom: 3, right: 4); let edg2 = UIEdgeInsets(top: 4, left: 3, bottom: 2, right: 1); let e = edg1 + edg2;
print("edg1: (edg1)");//edg1: UIEdgeInsets(top: 1.0, left: 2.0, bottom: 3.0, right: 4.0) print("edg2: (edg2)");//edg2: UIEdgeInsets(top: 4.0, left: 3.0, bottom: 2.0, right: 1.0) print("e: (e)");//e: UIEdgeInsets(top: 5.0, left: 5.0, bottom: 5.0, right: 5.0) ```
源码实现:
``` public extension UIEdgeInsets{
static func + (lhs: UIEdgeInsets, rhs: UIEdgeInsets) -> UIEdgeInsets { return UIEdgeInsets(lhs.top + rhs.top, lhs.left + rhs.left, lhs.bottom + rhs.bottom, lhs.right + rhs.right ); } } ```
四、总结
1、重载运算符可以将繁琐的操作简单化,复杂的操作封装化,属于质变的重构方式;
2、编程的核心是创造力,你创造各种工具函数的能力越强则工作越轻松,反之亦然。